HC Verma Class 11 Physics Solutions Chapter 10: Rotational Mechanics

HC Verma Solutions of Concept of Physics Part 1 Chapter -10 Rotational Mechanics

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HC Verma Class 11 Physics Solutions Chapter 10: Rotational Mechanics PDF

This page has detailed, step-by-step explanations of every question in HC Verma Class 11 Physics Solutions Chapter 10. For example, in the chapter “Rotational Mechanics” which is the first chapter of Volume 1 of HC Verma’s concept of physics for jee, all of the questions are solved and the steps are explained to help you learn. Utopper is a smart way for students to go over the whole Physics Syllabus again and again. The questions and answers help them study in a way that will help them do well on their tests.

In the HC Verma Class 11 Physics Solutions Chapter 10 “Rotational Mechanics” concept of physics, all of the questions are solved and the steps are explained to help you learn. On the Utopper website where students can get free Reference Book Solutions and other study materials like Revision notes, Sample papers, and Important Questions. Science will be easier to learn if you have access to HC Verma Solutions and solutions for other courses.

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Here is a pdf of HC Verma Class 11 Solutions for Chapter 10: Rotational Mechanics

HC Verma Class 11 Physics Solutions Chapter 10

About the chapter: HC Verma Class 11 Solutions Chapter 10

In this chapter, they talked about two important theorems based on the Moment of Inertia:

  • The Parallel Axes Theorem
  • The Perpendicular Axes Theorem

The perpendicular axis is used to find the moment of inertia of a solid object that lies perpendicular to a plane. On Utopper, you can learn more about the theorem of parallel axes.

When used with plane bodies, both of these theorems show that Iz = Ix + Iy.

Here, the axes (x,y,z) are all different from each other. And the axes of the lamina are x and y.

I = Mk2 is an equation that can be used to figure out a body’s radius of gyration. I stand for the moment of inertia, and M stands for the total weight.

Think about a pulley at a typical Indian well. A rope is wound around it, and one end is attached to a bucket. When you let go of the bucket, the pulley starts to turn. As the bucket gets closer to the water, the pulley turns faster until the bucket is in the water. Use the pulley to represent the system. The pulley’s center of mass is at its geometric center, which doesn’t move. The other parts of the pulley, on the other hand, move and speed up.

People say that the pulley is moving in a rotating motion. Also, the motion is not the same as it turns. Since ACM = 0, the force F that is acting on the pulley from the outside must also be 0. Even so, the pulley is not in a state of rotational balance. We will now learn about this kind of motion. 

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Ans – Students have used this book to study for JEE for the past twenty years, and they have all passed JEE. So, this book can’t be ignored. Once you’ve figured out how to solve the example problems, you can compare your answers to those in the book. If your answer is right, compare it to the solution to make sure you used the right steps to get there. If your answer is wrong, look at the other solutions to figure out “why” your answer is wrong. If you made a math or procedure mistake, you’ll need to find a way to fix it if you want to do well on an exam like the JEE.

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