RS Aggarwal Class 9 Solutions Chapter 14

RS Aggarwal Solutions for Class 9 Chapter 14 – Areas of Triangles and Quadrilaterals PDF

RS Aggarwal Class 9 Solutions Chapter-wise – Free PDF Download

RS Aggarwal Class 9 Solutions Chapter 14, “Area of Triangle and Quadrilateral,” is about the different types of triangles and quadrilaterals and their areas. This chapter is important for learning how to figure out the areas of important geometric shapes like isosceles triangles, rectangles, and so on. Students learn useful formulas for figuring out the areas of these geometric shapes, which are the basis of engineering drawing and architecture. This chapter teaches the basics of how geometry can be used to solve problems in the real world.

The RS Aggarwal Solutions for Class 9 Chapter 14 are easy to understand because they are clear and to the point. The answers can be found on the Utopper website. In Chapter 14, “Areas of Triangles and Quadrilaterals,” there are several ideas about triangles and parallelograms. It will help you figure out the area when you have a number and certain rules. You will learn about different figures that all have the same base and parallel lines.

There is only one exercise in the RS Aggarwal Class 9 Solutions Chapter 14 for Chapter 14. Find the area of different parallelograms and triangles to answer the questions.

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So Utopper’s RS Aggarwal Class 9 Solutions Chapter 14 can help you a lot. Our experts have made the answers easy to understand and step by step. You can trust this great book to help you fully understand Chapter 14.

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RS Aggarwal Class 9 Solutions Chapter 14 – Areas of Triangles and Quadrilaterals

RS Aggarwal Class 9 Solutions Chapter 14

Download a free PDF of RS Aggarwal Class 9 Solutions Chapter 14

In RS Aggarwal Class 9 Solutions Chapter 14, the main ideas learned are:

  • Area of different triangles and quadrilaterals
  • Area of a quadrilaterals using diagonals

These two topics are very important if you want to learn a lot about geometry and do well on tests. In this chapter, there are two exercises:

  • The first exercise is made up of 44 problems that show different ways to use formulas to find the area of triangles and other quadrilateral shapes.
  • The second exercise is a set of multiple-choice questions that test how well the student understands the ideas from the first exercise.
  • Class 9 Maths RS Aggarwal Solutions Chapter 14 has questions that are perfect for a lot of practise to do well on tests.

RS Aggarwal Solutions for Class 9 Chapter 14 includes the following important formulas:

1. The Area of triangle: ½ × b × h (where b is the triangle’s base and h is its height.)

2. The area of a triangle with equal sides: A triangle with equal sides is called an equilateral triangle.

  • Area of an equilateral triangle = (√3/4)a2
  • Height of an equilateral triangle = h = (a√3)/2

where an is the length of the two sides that are the same length and b is the length of the bottom.

3. Area of an isosceles triangle: Area = ½ × base × Height

The formula for finding the area of a triangle with three different sides is:
  • Let’s say the lengths of the sides of a triangle are a, b, and c.
  • The way Heron’s formula works is: The first step is to find the half of the triangle’s perimeter:
  • Semi-perimeter (S) = s = ½(a + b + c)
  • The second step is to use the above result and put it into Heron’s formula for the area of a triangle.
  • Area = √[s(s−a)(s−b)(s−c)]
There are seven different kinds of quadrilaterals, based on the lengths of their sides and angles, and each has a different way to figure out its area

parallelogram : It has two sides that are the same length and run parallel to each other.

  • Area of a parallelogram = base × height

Rectangle: It’s a parallelogram, and each of its four angles is 900.

  • Area of a rectangle = length × breadth

A Square is a rectangle whose sides are all the same length.

  • Area of a square = side2

A Rhombus is a parallelogram with four equal sides.

  • The area of a rhombus is A = base x height.
  • Area of rhombus using diagonals = A = ½ × d1 × d2

Trapezium: One pair of sides on a trapezium are parallel.

  • Area of trapezium = A = ½ (a + b) h
  • where a and b are the lengths of two sides that are parallel to each other and h is the height.

Kite: It has two pairs of sides that are the same length, but the sides that are next to each other are not the same.

  • Area of a kite = ½ × AC × BD
  • BD is a long diagonal and AC is a short one. 

FAQ ( Frequently Asked Questions )

1. How do you find the area of a rhombus if you know the length of one of its sides and one of its diagonals?

Ans – In this case, the rhombus can be split into two isosceles triangles whose sides and bases are the same length. Both triangles have the diagonal as their base.

By using the formula b/4 √(4a² – b²) to find the area of each isosceles triangle and adding them up, it is easy to find the area of the rhombus.

2. How Many Different Types of Quadrilaterals?

Ans – Quadrilaterals come in six different shapes: the parallelogram, rectangle, square, rhombus, trapezium, and kite.

3. Why is Class 9 RS Aggarwal so important?

Ans – RS Aggarwal is very important for students in Class 9 because it has detailed explanations of important ideas that students need to know. It also has illustrations that help students understand what they are reading. The RS Aggarwal book has a lot of worked-out examples that help students understand how the ideas they’ve learned work in the real world. Lastly, the exercises have a lot of unanswered questions that will help students figure out if they have learned or not.